A Collection of Diophantine Problems With Solutions (Classic Reprint) - Couverture souple

Matteson, James

 
9781333611101: A Collection of Diophantine Problems With Solutions (Classic Reprint)

Synopsis

Master challenging Diophantine problems with clear, step-by-step solutions. This collection presents classic puzzles and their long-form methods, showing how to approach tough number problems with structured reasoning.


From sums of cubes to simultaneous square and cube relations, the book assembles problems and full solutions that illustrate techniques, substitutions, and problem-solving strategies. It also includes notes on methods used, historical context, and ways to generalize the reasoning to related challenges.



  • See concrete worked examples of finding numbers whose pairwise sums yield cubes.

  • Learn how to transform problems into solvable equations and follow the logical steps to solutions.

  • Explore multiple problem types, including those about sums of squares and mixed polynomial relations.

  • Understand the origins and development of classical Diophantine techniques through practical demonstrations.


Ideal for readers who enjoy number theory puzzles, historical math curiosities, and hands-on problem solving.

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Présentation de l'éditeur

1 Diophantine Problem, It is required to find four affirmative integer numbers, such that the sum of every two of them shall be a cube. Solution. If we assume the first^Cx3^)/3-), the second^^x3-y3--z* ), the third=4(-z3+y3+*'), and the fourth=ws-iOM"^-*)5 then> the first added to the second=B8, the first added to the third=)/3, the second added to third=23, and the first added to the fourth=ir Thus four of the six required conditions are satisfied in the notation. It remains, then, to make the second plus the fourth= v3-y3Jrz*=cnbe, say=ic3, and the third plus the fourth^*3- 23=cube, say=?«3. Transposing, we have to resolve the equalities v3--£=w3--if=u?--oi?; and with values of x, y, z, in such ratio, that each two shall be greater than the third. Let us first resolve, in general terms, the equality «'-}-23=w3-|-y3. Taking v=a--b, z=a-b, w-c--d, y=c-d, the equation, after-dividing by 2, becomes a(a2-)-3i2)==e(c2-J-3f72). Now assume a-Sn])--Smq, b=mp-3nq, c=3nr

About the Publisher

Forgotten Books is a publisher of historical writings, such as: Philosophy, Classics, Science, Religion, History, Folklore and Mythology.

Forgotten Books' Classic Reprint Series utilizes the latest technology to regenerate facsimiles of historically important writings. Careful attention has been made to accurately preserve the original format of each page whilst digitally enhancing the difficult to read text. Read books online for free at www.forgottenbooks.org

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